I bred one of my pairs a sky, violet, yellowface I, spangle female and a normal sky split ino and they produced 4 lovely chicks. 2 males (1 exactly like mum and a cobalt blue spangle) and 2 females (1 cobalt blue normal and a creamino).
I was just wondering will the 2 male babies be split for ino. I know that the ino gene is sex linked, which means there needs to be 2 of the ino gene for a male to show it visually, is that right.
You are correct, males need two copies from each parent to show ino visually. There's a 50/50 chance of each baby boy being split ino. The only way to find out is to breed them when they're older And see if they produce ino daughters.
Just a thought... 2 sky birds can only produce sky offspring (unless grey is involved), so the cobalts must be sky violets or the sky violet parent is a cobalt....
Krystal is right about the ino, half the boys will be split for it as the father has one ino gene and one non-ino gene on his 2 sex chromosomes.
Mum is definitely a sky, I have other budgies that are cobalt and her colour is lighter than them. So I guess the babies could be sky,violets.
There may be grey involved somewhere as I am hand rearing a baby from their 2nd clutch (it has splayed legs, so pulled it for treatment) and it looks as though it is going to be grey, it may not be but at the moment (3 weeks) it's not showing much colour.
Have attached photo of 2 maybe cobalt babies it only shows there backs but can see a little of their colour. It's the only photo I have at the moment. I can get another this afternoon of there front if that will help.
That's what I thought about the grey. This chick is defiantly from this pair as they have been in a breeding cage by themselves, I don't colony breed and never will.
Obviously the chick hasn't got enough of its feathers to show its colour yet, although I have just noticed a little of a bluish colour on the start of it tail feathers so maybe it will be a sky violet too. This is a photo of the little one.
Last edited by budgielovers; 06-22-2015 at 02:17 AM.